在iOS 6中，以前工作正常的訪問(wèn)通訊錄的iPhone程序可能會(huì)出錯(cuò)，現(xiàn)象是程序啟動(dòng)時(shí)不提醒用戶是否允許程序訪問(wèn)通訊錄，同時(shí)在“設(shè)置->隱私->通訊錄”中看不到你的程序。另外，對(duì)通訊錄進(jìn)行操作的代碼會(huì)報(bào)類似于以下消息的錯(cuò)誤：

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    Could not compile statement for query (ABCCopyArrayOfAllInstancesOfClassInSourceMatchingProperties):

SELECT ROWID, Name, ExternalIdentifier, Type, ConstraintsPath, ExternalModificationTag, ExternalSyncTag, AccountID, Enabled, SyncData, MeIdentifier, Capabilities FROM ABStore WHERE Enabled = ?;
  

其原因是iOS 6加強(qiáng)了通訊錄訪問(wèn)控制，要求開(kāi)發(fā)人員顯式聲明需要訪問(wèn)通訊錄，方法是調(diào)用 ? ABAddressBookRequestAccessWithCompletion

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方法，具體參見(jiàn)官方文檔：

http://developer.apple.com/library/ios/#releasenotes/General/RN-iOSSDK-6_0/index.html

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下面是對(duì)應(yīng)的樣例代碼，一般來(lái)講需要將這段代碼放置在程序啟動(dòng)部分，在程序啟動(dòng)過(guò)程中提示用戶本程序需要訪問(wèn)設(shè)備上的通訊錄：

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    ABAddressBookRef addressBook = ABAddressBookCreate();

    

        

        __block BOOL accessGranted = NO;

    if (ABAddressBookRequestAccessWithCompletion != NULL) {

        

        // we're on iOS 6

        NSLog(@"on iOS 6 or later, trying to grant access permission");

        

        dispatch_semaphore_t sema = dispatch_semaphore_create(0);

        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {

            accessGranted = granted;

            dispatch_semaphore_signal(sema);

        });

        dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);

        dispatch_release(sema);

    }

    else { // we're on iOS 5 or older

        

        NSLog(@"on iOS 5 or older, it is OK");

        accessGranted = YES;

    }

    

    if (accessGranted) {

        

        NSLog(@"we got the access right");

    }

    


  

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iOS6 中如何獲得通訊錄訪問(wèn)權(quán)限