將? timett? =? "30/07/2019 11:26:35"? ? 轉換成自己想要的格式如? ? timenn = "30/07/2019 11:26"

            
              # -*- encoding=utf8 -*-
import time
timtt="30/07/2019 11:26:35"

time1 = time.strptime(timtt, '%d/%m/%Y %H:%M:%S')   # 函數根據指定的格式把一個時間字符串解析為時間元組。
time2 = time.strftime('%d/%m/%Y %H:%M', time1)      #函數接收以時間元組，并返回以可讀字符串表示的當地時間，格式由參數格式決定
time3 = time.strftime('%Y/%m/%d %H:%M', time1)
time4 = time.strftime('%Y-%m-%d %H:%M', time1)

print(time1, type(time1))
print(time2, type(time2))
print(time3, type(time3))
print(time4, type(time4))
            
          

?輸入結果是:

            
              time.struct_time(tm_year=2019, tm_mon=7, tm_mday=30, tm_hour=11, tm_min=26, tm_sec=35, tm_wday=1, tm_yday=211, tm_isdst=-1) 
              
                
30/07/2019 11:26 
                
                  
2019/07/30 11:26 
                  
                    
2019-07-30 11:26 
                    
                  
                
              
            
          

?